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2x^2+2x(-480)=0
We multiply parentheses
2x^2-960x=0
a = 2; b = -960; c = 0;
Δ = b2-4ac
Δ = -9602-4·2·0
Δ = 921600
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$$\sqrt{\Delta}=\sqrt{921600}=960$$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-960)-960}{2*2}=\frac{0}{4} =0 $$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-960)+960}{2*2}=\frac{1920}{4} =480 $
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